Question

Connor wants to attend the town carnival. The price of admission to
the carnival is $4.50, and each ride costs an additional 79 cents.
If he can spend at most $16.00 at the carnival, which inequality can
be used to solve for r, the number of rides Connor can go on, and
what is the maximum number of rides he can go on?
(1) 0.79 + 4.50r ≤ 16.00; 3 rides
(2) 0.79 + 4.50r ≤ 16.00; 4 rides
(3) 4.50 + 0.79r ≤ 16.00; 14 rides
(4) 4.50 + 0.79r ≤ 16.00; 15 rides

Answer 1

Answer:

Option 3.

Step-by-step explanation:

Let r be the number of rides Connor can go on.

The price of admission to the carnival is $4.50, and each ride costs an additional 79 cents.

Total cost of admission and r rids is

$\text{Total cost}=4.50+0.79r$

Connor can spend at most $16.00 at the carnival. So, total cost must be less than or equal to $16.00.

$4.50+0.79r\leq 16.00$

Subtract 4.50 from both sides.

$4.50+0.79r-4.50\leq 16.00-4.50$

$0.79r\leq 11.50$

Divide both sides by 0.79.

$r\leq \frac{11.50}{0.79}$

$r\leq 14.55$

The maximum number of rides he can go on is 14. Therefore, the correct option is 3.