Question

What is the minimum total energy released when
an electron and its antiparticle (positron)
annihilate each other?
(1) 1.64 × 10^–13 J (3) 5.47 × 10^–22 J
(2) 8.20 × 10^–14 J (4) 2.73 × 10^–22 J

Answer 1

Answer:

(1) $1.64 \times 10^{-13} J$

Explanation:

Energy released in this process is given by

$Q = \Delta m c^2$

here we have

$\Delta m = 9.1 \times 10^{-31} kg$

since here mass of two electrons converted into energy so we have

$Q = 2(9.1 /times 10^{-31})(3\times 10^8)^2$

$Q = 1.64 \times 10^{-13} J$

so here energy released is the energy of rest mass energy due to two charges i.e. electrons and positrons

Answer 2

The minimum total energy released when an electron and its antiparticle (positron) annihilate each other is 1.64 x 10⁻¹³ J.

What is the minimum total energy released?

The minimum total energy released when an electron and its antiparticle (positron) annihilate each other is calculated as follows;

E = Δmc²

where;

• m is the mass of the two electrons
• c is speed of light

E = (2 x 9.11 x 10⁻³¹) x (3 x 10⁸)²

E = 1.64 x 10⁻¹³ J

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