Question

210.0 °C a gas has a volume of 8.00 L. What is the volume of this gas at -23.0°C?

Answer 1

V₁ = 8.00 L

T₁ = 210.0ºC + 273 = 483 K

V₂ = ?

T₂ = - 23.0ºC + 273 = 250 K

V₁/ T₁ = V₂ / T₂

8.00 / 483 = V₂ / 250

483 x V₂ = 8.00 x 250

483 V₂ = 2000

V₂ = 2000 / 483

V₂ = 4.14 L

hope this helps!