Answer:
[tex]3.6\times 10^{-4}[/tex] moles of Threobromine are present in chocolate bar
Explanation:
Molar mass of Theobromine = ([tex]7\times[/tex]molar mass of C)+([tex]8\times[/tex]molar mass of H)+([tex]4\times[/tex]molar mass of N)+([tex]2\times[/tex]molar mass of O) = ([tex]7\times[/tex]12g/mol)+([tex]8\times[/tex]1g/mol)+([tex]4\times[/tex]14g/mol)+([tex]2\times[/tex]16g/mol) = 180 g/mol
We know that, number of moles of a compound is the ratio of mass to molar mass of the compound.
So, 0.064 g of Threobromine = [tex]\frac{0.064}{180}[/tex] moles of Threobromine = [tex]3.6\times 10^{-4}[/tex] moles of Threobromine