Question

In an apparent effort to earn an appearance on the Destroyed in Seconds show, Caleb attempts a bicycle maneuver in which he jumps between two ramps whose elevated edges are located a distance of 1.8 meters apart. The ramps are angled at 35° and located at the same height. Determine the speed (in m/s and mi/hr) that Caleb must acquire to accomplish this stunt. (Given: 1.00 m/s = 2.24 mi/hr)

Answer 1

Answer:u=4.32 m/s

Explanation:

Given

Distance between two edges=1.8 m

launch angle$=35^{\circ}$

Let initial speed be u

Considering Caleb as projectile

$Range=\frac{u^2\sin 2\theta }{g}$

$u^2\sin 70=1.8\times 9.8$

$u^2=18.772$

$u=4.32 m/s=9.70 mi/hr$