The length of the diagonal is 13.9 inches, rounded to the tenths
Step-by-step explanation:
Let us revise the proprieties of the rectangle
1. Each two opposite sides are equal
2. Each two opposite sides are parallel
3. Its four angles are right angles
4. Its two diagonals are equal
You can find the length of its diagonal by using Pythagoras Theorem
[tex](hypotenuse)=\sqrt{(leg1)^{2}+(leg2)^{2}}[/tex]
∵ The dimensions of a rectangular piece of paper are 8.5 inches by
11 inches
∴ Its length "l" = 8.5 inches and its width "w" = 11 inches
- The diagonal of the rectangle is the hypotenuse of the right triangle
whose legs are the length and the width
∵ The length of the diagonal = [tex]\sqrt{l^{2}+w^{2}}[/tex]
- Substitute the values of l and w in the rule Pythagoras Theorem
∴ The length of the diagonal = [tex]\sqrt{(8.5)^{2}+(11)^{2}}[/tex]
∴ The length of the diagonal = 13.9 inches
The length of the diagonal is 13.9 inches, rounded to the tenths
Learn more:
You can learn more about rectangles in brainly.com/question/12919591
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