Answer:
The maximum mass of carbon dioxide that could be produced by the chemical reaction is 70.6gCO_{2}
Explanation:
1. Write down the balanced chemical reaction:
[tex]2C_{6}H_{14}_{(l)}+19O_{2}_{(g)}=12CO_{2}_{(g)}+14H_{2}O_{(g)}[/tex]
2. Find the limiting reagent:
- First calculate the number of moles of hexane and oxygen with the mass given by the problem.
For the hexane:
[tex]70.0gC_{6}H_{14}*\frac{1molC_{6}H_{14}}{86.2gC_{6}H_{14}}=0.81molesC_{6}H_{14}[/tex]
For the oxygen:
[tex]81.3gO_{2}*\frac{1molO_{2}}{32.0gO_{2}}=2.54molesO_{2}[/tex]
- Then divide the number of moles between the stoichiometric coefficient:
For the hexane:
[tex]\frac{0.81}{2}=0.41[/tex]
For the oxygen:
[tex]\frac{2.54}{19}=0.13[/tex]
- As the fraction for the oxygen is the smallest, the oxygen is the limiting reagent.
3. Calculate the maximum mass of carbon dioxide that could be produced by the chemical reaction:
The calculations must be done with the limiting reagent, that is the oxygen.
[tex]81.3gO_{2}*\frac{1molO_{2}}{32gO_{2}}*\frac{12molesCO_{2}}{19molesO_{2}}*\frac{44.0gCO_{2}}{1molCO_{2}}=70.6gCO_{2}[/tex]