Question

A 50-kg student stands on a scale in an elevator. At the instant the elevator has a downward acceleration of 1.0 m/s2 and an upward velocity of 3.0 m/s, the scale reads approximately(A) 350 N (B) 450 N (C) 500 N (D) 550 N (E) 650 N

Answer 1

Answer:D-550 N

Explanation:

Given

mass of student=50 kg

at particular instant elevator is moving downward with acceleration of  1 m/s^2

Net weight of man shown by scale will be more than his actual weight as elevator is decelerating

let N be the normal reaction on man thus

$N-mg=ma$

$N=m(g+a)$

$N=50\times (10+1)$

$N=550 N$

and Normal reaction will be shown by scale as apparent weight

Answer 2

Option D) 500 N is correct.

Given :

Mass = 50 Kg

Acceleration =  $\rm -1 \; m/sec^2$

Velocity = 3 m/sec

Solution :

F = ma            (from Newton's second law)

N - mg = ma

N = m(g - a)

$\rm N = 50(10+1)$

N = 550 N

Therefore option D) 500 N is correct.

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