Question

The school is selling potted plants as a fundraiser. Kara sold 12 ferns and 8 ivy plants for $260. Paul sold 15 ivy plants and 6 ferns for $240. What is the selling price of each plant?

Answer 1

Answer:

Fern = $15

Ivy= $10

Step-by-step explanation:

Let f = ferns and v = ivy

12f + 8v = $260 ------1

6f + 15v = $240 -------2

Using elimination method

multiply eqn 1 by 15 and eqn 2 by 8

180f +120v = 3900

48f + 120v = 1920

Subtracting

132f = 1980

f = $15

From eqn 1

12*15 + 8v = 260

180 + 8v = 260

8v = 80

v = $10

Answer 2

The selling price of the ferns is $12.5, while the selling price of the ivy plants is $11

Represent the ferns with x and the ivy plants with y.

So, we have the following system of equations

12x + 8y = 260

6x + 15y = 240

Multiply the second equation by 2

12x + 30y = 480

Subtract the first equation from the third equation

12x - 12x + 30y - 8y = 480 - 260

Evaluate the differences

22y = 220

Evaluate the quotient

y = 11

Recall that:

6x + 15y = 240

So, we have:

6x + 15*11 = 240

6x + 165 = 240

Evaluate the like terms

6x = 75

Divide through by 6

x = 12.5

Hence, the selling price of the ferns is $12.5, while the selling price of the ivy plants is $11

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