Question

You are standing in a street corner. And egg falls and splats on the street. Being an expert in egg disintegration you estimate it was traveling 22 m/s when it hit. You assume the egg was dropped. From what height was it dropped

Answer 1

The egg was dropped from a height of 24.7 m (free fall motion)

Explanation:

The motion of the egg is a free fall motion (uniformly accelerated motion), so we can use the following suvat equation:

$v^2-u^2=2as$

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the displacement

For the egg in this problem, we have:

u = 0 is the initial velocity

v = 22 m/s is the final velocity

$a=g=9.8 m/s^2$ is the acceleration of gravity

s is the vertical displacement (the height from which the egg was dropped)

Solving for s, we find:

$s=\frac{v^2-u^2}{2a}=\frac{22^2-0}{2(9.8)}=24.7 m$

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