Answer:
Step-by-step explanation:
m(x)=\sqrt{2x²-13x-24}
Domain :2x²-13 x-24≥0
2x²-16x+3 x-24≥0
2x(x-8)+3(x-8)≥0
(x-8)(2x+3)≥0
both the factors are of same sign as it is ≥0
case 1.let x-8≥0⇒x≥8
and 2x+3≥0⇒x≥-3/2
together ⇒x≥8
case 2.
x-8≤0,⇒x≤8
and 2x+3≤0,⇒x≤-3/2
together they give x≤-3/2
so solution is (-∞,-3/2]∪[8,∞)
