Answer:
The speed of the car is 7.84 m/s
Solution:
As per the question:
Length of the bridge, l = 5.0 m
Distance, d = 2 m
Now,
Time taken by the car to reach 2 m lower is given by the kinematic eqn:
[tex]d = ut + \frac{1}{2}at^{2}[/tex]
where
u = initial velocity = 0 m/s
t = time taken
a = g = [tex]9.8\ m/s^{}[/tex]
Now,
[tex]2 = 0.t + \frac{1}{2}\times 9.8\times t^{2}[/tex]
[tex]t = 0.638\ s[/tex]
Now, we kow that the car will cover the distance equal to the length of the bridge, i.e., 5 m
Speed of the car is given by:
[tex]v = \frac{distance\ covered}{time\ taken}[/tex]
[tex]v = \frac{5.0}{0.638} = 7.84\ m/s[/tex]