Question

Two parallel paths 20 m apart run east–west through the woods. Brooke walks east on one path at 6 km/h, while Jamail walks west on the other path at 7 km/h. If they pass each other at time ????=0, how far apart are they 11 s later, and how fast is the distance between them changing at that moment? (Use decimal notation. Give your answer to three decimal places.)

Answer 1

Answer:

46.218 m

Explanation:

Distance = Speed × Time

$Distance=\frac{6}{3.6}\times 11=\frac{55}{3}\ m$

Distance traveled by Brooke is $\frac{55}{3}\ m$

$Distance=\frac{7}{3.6}\times 11=\frac{70}{3}\ m$

Distance traveled by Jamail is $\frac{70}{3}\ m$

From Pythagoras theorem

$s=\sqrt{20^2+\left(\frac{125}{3}\right)^2}\\\Rightarrow s=46.218\ m$

The distance between Brooke and Jamail after 11 seconds is 46.218 m