Question

Trained dolphins are capable of a vertical leap of 7.0 m straight up from the surface of the water-an impressive feat.Suppose you could train a dolphin to launch itself out of the water at this same speed but at an angle. What maximum horizontal range could the dolphin achieve?

Answer 1

Answer:

$R_{max} = 14 m$

Explanation:

Maximum height reached by Dolphins is given as

$H = 7 m$

now we know that

$H = \frac{v^2}{2g}$

$7 = \frac{v^2}{2g}$

$v^2 = 2(7)(9.81)$

$v = 11.72 m/s$

now the formula of range is given as

$R = \frac{v^2 sin(2\theta)}{g}$

now we know that for maximum range the angle should be 45 degree

so we will have

$R_{max} = \frac{v^2}{g}$

$R_{max} = 7 \times 2$

$R_{max} = 14 m$