contestada

A 0.40-kg object is traveling to the right (in the positive direction) with a speed of 4.0 m/s. After a 0.20 s collision, the object is traveling to the left at 3.0 m/s. What is the magnitude of the impulse (in N-s) acting on the object? The answer must be positive. (NEVER include units in the answer to a numerical question.)

Respuesta :

Explanation:

It is given that,

Mass of the object, m = 0.4 kg

Speed of the object, u = 4 m/s

After the collision, the object is travelling, v = -3 m/s (to left)

Time, t = 0.2 seconds

Let J is the impulse acting on the object. We know that the impulse of an object is equal to the change in momentum. It can be calculated as :

[tex]J=m(v-u)[/tex]

[tex]J=0.4(-3-4)[/tex]

J = -2.8 kg-m/s

|J| = 2.8 kg-m/s

So, the impulse acting on the object has a magnitude of 2.8 kg-m/s. Hence, this is the required solution.

asuwafohjames

The impulse acting on the object is 2.8 N-s.

What is impulse?

Impulse can be defined as the product mass and the change in velocity of a body.

To calculate the impulse acting on the object, we use the formula below.

Formula:

  • I = m(v-u)........... Equation 1

Where:

  • I = Impulse acting on the object
  • m = mass of the object
  • v = final velocity
  • u = initial velocity

From the question,

Given:

  • m = 0.40 kg
  • v = 4.0 m/s
  • u = -3.0 m/s (to the left)

Substitute these values into equation 1

  • I = 0.4[4-(-3)]
  • I = 0.4(4+3)
  • I = 2.8 N-s

Hence, The impulse acting on the object is 2.8 N-s.

Learn more about impulse here: https://brainly.com/question/904448

ACCESS MORE