Answer:
0.248 m
Explanation:
The period of a simple pendulum is given by
[tex]T=2\pi \sqrt{\frac{L}{g}}[/tex]
where
L is the length of the pendulum
g is the acceleration of gravity
The pendulum in the problem passes its lowest point twice every second: this means: this means that it makes one complete oscillation in one second, so its period is 1 second:
T = 1 s
And using
[tex]g=9.8 m/s^2[/tex]
We can rearrange the equation above to find L, the length of the pendulum:
[tex]L=\frac{T^2 g}{4\pi^2}=\frac{1^2(9.8)}{4\pi^2}=0.248 m[/tex]
