Question

For safety reasons, the base of a 24-foot ladder must be placed at least 8 feet
from the wall. To the nearest tenth of a foot, how high can a 24-foot ladder
safely reach

Answer 1

Answer:

Step-by-step explanation:

We can solve this problem using the pythagorean theorem.

What you need to know:

-The hypotenuse is 24.

-One of the bases is 8.

Steps for Solving:

8$8^{2} + b^{2} = 24^{2} \\\\64 + b^{2} = 576\\\\b^{2} = 576 - 64\\\\b^{2} = 512\\\\b = \sqrt{512} \\\\b = 16 \sqrt{2} \\\\b = 22.63$

Edit: disregard the 8 infront of b in the final answer. I'm not sure how to fix the typo lol

Answer 2

Answer:

22.6

Step-by-step explanation:

c²=a²+b²

24²=8² + x²

576 = 64 + x²

x² = 576 - 64

x² = 512

x = 22.627...

= 22.63 foot

sorry if it's not correct