For this case we find the slopes of each of the lines:
The g line passes through the following points:
[tex](x_ {1}, y_ {1}) :( 3,2)\\(x_ {2}, y_ {2}) :( 5,9)[/tex]
So, the slope is:
[tex]m = \frac {y_ {2} -y_ {1}} {x_ {2} -x_ {1}} = \frac {9-2} {5-3} = \frac {7} {2}[/tex]
Line h passes through the following points:
[tex](x_ {1}, y_ {1}) :( 9,10)\\(x_ {2}, y_ {2}) :( 2,12)[/tex]
So, the slope is:
[tex]m = \frac {y_ {2} -y_ {1}}{x_ {2} -x_ {1}} = \frac {12-10} {2-9} = \frac {2} {- 7} = - \frac {2} {7}[/tex]
By definition, if two lines are parallel then their slopes are equal. If the lines are perpendicular then the product of their slopes is -1.
It is observed that lines g and h are not parallel. We verify if they are perpendicular:
[tex]\frac {7} {2} * - \frac {2} {7} = \frac {-14} {14} = - 1[/tex]
Thus, the lines are perpendicular.
Answer:
The lines are perpendicular.