Question

The circle below is centered at the point (8,4) and has a radius of length 4.
What is its equation?
O A. (x-4)2 + (y + 8)2 = 4
O B. (x-8)2 + (y-4)2 =
16
O C. (x-4)2 + (7-8)2 =
10
42
O D. (x+8)2 + (9-4)2 =
16
SUBMIT

Answer 1

Answer:

$\textbf{The equation of the circle is: {(x-8)}^2 + {(y-4)}^2 = 16 .}$

Step-by-step explanation:

$\textup{The equation of a circle is given by:}\\ c = \sqrt{{(x-h)}^2 + {(y-k)}^2} = r^2 \\\textit{where (h,k) represents the centre of the circle and r the radius.}\\\textup{Given the centre of the circle is (8,4) and radius is 4 .} \therefore We have c = \sqrt{{(x-8)}^2 + {(y-4)}^2} = 4^2 \implies {(x-8)}^2 + {(y-4)}^2 = 16$