Question

Question 1 What is −12÷2/3
Question 2 What is -8/3÷7/12
Question 3 Divide.8.64÷(−0.27)
Question 4 Starting at sea level, a submarine descended at a constant rate to a depth of −3/4 mile relative to sea level in 5 minutes.What was the submarine's depth relative to sea level after the first minute?
Enter your answer in a fraction in simplest form.
Question 5 One cold night the temperature was 0 degrees at 8 p.m. The temperature dropped at a constant rate from 8 p.m. to midnight. At midnight the temperature was −16.8 degrees.
What was the temperature at 9 p.m.?

Answer 1

Answer:

Step-by-step explanation:

1) −12÷2/3  = -12 * 3/2 = -6*3 = -18

2) -8/3÷7/12 = -8/3 * 12/7 = -8*12 / 3*7 = -96/21

3)8.64÷(−0.27) = 8.64/-0.27 = 8.64*100/-0.27*100 =864/-27 = - 32

4) The submarine's depth relative to sea level after the first minute = -3/4 divided by 5

= -3/4 *1/5 =-3/20 = -0.15 miles