Answer:
(-3,0) and (2,-1)
Step-by-step explanation:
For (-3,0) x=-3 , y=0:
Putting in given inequality :
y < x2 - 4x + 3
0 < -3^2 -4*-3 +3 ("-" into "-" becomes "+")
0 < 9 +12 +3
0< 24 true
For (2, -1) x=2 , y= -1
Putting in given inequality :
y < x2 - 4x + 3
-1 < 2^2 -4(2) +3
-1 < 4 -6 +3
-1 < 7-6
-1 < 1 true
For (1,0) x=1 y=0
Putting in given inequality :
y < x2 - 4x + 3
0 < 1^2 -4(1)+ 3
0< 1- 4 + 3
0< 4 - 4
0 < 0 false
Hence, (-3,0) and (2,-1) are in the solution set of y < x2 - 4x + 3.
I hope it will help you!
