Respuesta :
Answer:
[tex]b=\frac{2}{3}[/tex] and [tex]b=-2[/tex]
Step-by-step explanation:
Given:
[tex]4(3b+2)^{2}=64[/tex]
In order to find the values of b, we need to solve the equation for b.
Divide both sides by 4.
This gives,
[tex]4(3b+2)^{2}=64\\ \frac{4(3b+2)^{2}}{4}=\frac{64}{4}\\ (3b+2)^{2}=16 [/tex]
Taking square root both sides, we get,
[tex]\sqrt{(3b+2)^2}=\sqrt{16}\\3b+2=\pm 4\\3b=\pm 4-2\\b=\frac{-2\pm 4}{3}[/tex]
Now, [tex]b=\frac{-2+4}{3}\textrm{ or } b=\frac{-2-4}{3}\\b=\frac{2}{3}\textrm{ or } b=\frac{-6}{3}\\b=\frac{2}{3}\textrm{ or } b=-2[/tex]
