Answer:
No solutions
Step-by-step explanation:
We need to eliminate one of the variables to solve the system. To do so, let's multiply the first equation by 8, the second equation by 4
- 2x + y + 5z = 4 (1) x 8
- 3x − 2y + 2z = 2 (2) x 4
- 5x − 8y − 4z = 1 (3)
The system becomes:
- 16x + 8y + 40z = 32 (1)
- 12x - 8y + 8z = 8 (2)
- 5x - 8y - 4z = 1 (3)
Add (1) and (2), subtract (3) from (2) to eliminate y
- 28x + 48z = 40 (4)
- 7x + 12z = 7 (5)
Then multiply the equation (5) by 4 to compare with(4)
Comparing the equations (4) and (5) we see it has no solutions as both variables have same coefficient but with different sum, 28≠40
