Question

Rhett is solving the quadratic equation 0= x2 – 2x – 3 using the quadratic formula. Which shows the correct substitution of the values a, b, and c into the quadratic formula?

Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction

StartFraction 2 plus or minus StartRoot (negative 2) squared minus 4(1)(negative 3) EndRoot Over 2(1) EndFraction
StartFraction negative 2 plus or minus StartRoot (negative 2) squared minus 4(1)(negative 3) EndRoot Over 2(1) EndFraction
StartFraction 2 plus or minus StartRoot negative 2 squared minus 4(1)(negative 3) EndRoot Over 2(1) EndFraction
StartFraction negative 2 plus or minus StartRoot negative 2 squared minus 4(1)(negative 3) EndRoot Over 2(1) EndFraction

Answer 1

Answer:

StartFraction 2 plus or minus StartRoot (negative 2) squared minus 4(1)(negative 3) EndRoot Over 2(1) EndFraction

Step-by-step explanation:

General quadratic equation: ax^2 + bx + c

where a is the coefficient of the quadratic term, b is the coefficient of the linear term and c is the independent term. Here the equation is: x^2 – 2x – 3, so a = 1, b = -2 and c = -3

Quadratic formula:

$x = \frac{-b \pm \sqrt{b^2-4(a)(c)}}{2(a)}$

Replacing

$x = \frac{2 \pm \sqrt{(-2)^2-4(1)(-3)}}{2(1)}$

Answer 2

Answer:

A is the answer

Step-by-step explanation:

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