Ramiya is using the quadratic formula to solve a quadratic equation. Her equation is x = StartFraction negative 3 plus or minus StartRoot 3 squared minus 4(1)(2) EndRoot Over 2(1) EndFraction after substituting the values of a, b, and c into the formula. Which is Ramiya’s quadratic equation?

Quadratic formula: x = StartFraction negative b plus or minus StartRoot b squared minus 4 a c EndRoot Over 2 a EndFraction

0 = x2 + 3x + 2
0 = x2 – 3x + 2
0 = 2x2 + 3x + 1
0 = 2x2 – 3x + 1

Respuesta :

Answer:

A

Step-by-step explanation:

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The quadratic equation with a formula [tex]x=\frac{-3\pm\sqrt{3^2-4(1)(2)} }{2(1)}[/tex]

What is a quadratic function?

A quadratic function is in the form:

y = ax² + bx + c

The solution is at:

[tex]x =\frac{-b\pm\sqrt{b^2-4ac} }{2a}[/tex]

Given that the quadratic formula is:

[tex]x=\frac{-3\pm\sqrt{3^2-4(1)(2)} }{2(1)}[/tex]

Hence a = 1, b = -3, c = 2

The quadratic equation with a formula [tex]x=\frac{-3\pm\sqrt{3^2-4(1)(2)} }{2(1)}[/tex] is x² - 3x + 2 = 0

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