Respuesta :
arith. series for odd number
An = 1 + 2(n-1) ; A1 = 1
sum to n terms
Sn = (An + A1)n/2 ;
An=59, n = 29
An = 1 + 2(n-1) ; A1 = 1
sum to n terms
Sn = (An + A1)n/2 ;
An=59, n = 29
Answer:
sum = 900
Step-by-step explanation:
The sum of all odd number can be solved using arithmetic progression formula.
Odd numbers are numbers that cannot be exactly divided by 2 .That means odd number have remainder when divide by 2.
The first odd number is 1
The second is 3
The sequence goes like this
1, 3, 5, 7, 9, 11, 13, 15, 17, 19 , 21 .................................59
a = 1
d = 2
where
a = first term
d = common difference
let us find the number of terms before finding the sum
nth term = a + (n - 1)d
59 = 1 + (n - 1)2
59 = 1 + 2n - 2
59 + 2 - 1 = 2n
60 = 2n
n = 60/2
n = 30
Sum = n/2(a+L)
where L = last term
sum = 30/2(1 + 59)
sum = 15(60)
sum = 900