Answer:
They have same density
Explanation:
The density of an object is defined as
[tex]d=\frac{m}{V}[/tex]
where
m is the mass of the object
V is its volume
Let's call [tex]m_c[/tex] and [tex]V_c[/tex] the mass and the volume of ball C, respectively. Therefore, the density of ball C is:
[tex]d_c = \frac{m_c}{V_c}[/tex]
We know that the volume of ball C is 3 times the volume of ball D, so
[tex]V_c = 3 V_d \rightarrow V_d = \frac{V_c}{3}[/tex]
And we also know that ball D has 1/3 the mass of ball C:
[tex]m_d = \frac{m_c}{3}[/tex]
So, the density of ball D is:
[tex]v_d = \frac{m_d}{V_d}=\frac{m_c/3}{V_d/3}=\frac{m_c}{V_c}=d_c[/tex]
Therefore, the two balls have same density.