For this case we have to:
The faces of a brick are rectangular in shape. When the brick is positioned in space, the area it occupies will be given by the area of one of its faces. By definition, the area of a rectangle is given by:
[tex]A = a * b[/tex]
Where:
a: It is the length of the rectangle
b: It is the width of the rectangle
According to the data we have to:
[tex]a = 8 \ in\\b = 3 \frac {1} {2} \ in = \frac {6 + 1} {2} = \frac {7} {2} \ in[/tex]
Thus, the area that the brick would cover is:
[tex]A = 8 * \frac {7} {2}\\A = \frac {56} {2}\\A = 28 \ in ^ 2[/tex]
Answer:
[tex]A = 28 \ in ^ 2[/tex]
