To solve this system of equations using substitution, y value to be substituted is 2x – 7.
Solution:
Given, two system of equations are 4x = 5 – 2y and y – 2x + 7 = 0
We have to find what substitution have to be done in place of y of the first equation to solve the given system of equations.
Now, let us derive the y value from 2nd equation ⇒ y – 2x + 7 = 0 ⇒ y = 2x – 7
We have got the y value, and we can substitute it in 1st equation ⇒ 4x = 5 – 2(2x – 7)
4x = 5 – 4x + 14
4x + 4x = 5 + 14
8x = 19
[tex]x=\frac{19}{8} \text { and } y=2\left(\frac{19}{8}\right)-7=\frac{19}{4}-7=\frac{19-28}{4}=\frac{-9}{4}[/tex]
So, solution for system of equations is [tex]\left(\frac{19}{8}, \frac{-9}{4}\right)[/tex]
Hence, the y value to be substituted is 2x – 7.