Given that m∠NMP=(3x+8)∘ and m∠OMP=(4x−6)∘, identify m∠NMO.

NMP = OMP
3x +8 = 4x -6
Subtract 3x from both sides:
8 = x -6
Add 6 to both sides:
x = 14
Now solve for one equation:
3x +8 = 3(14) +8 = 42+8 = 50
NMO is the sum of NMP and OMP
NMO = 50 +550 = 100 degrees.
The m∠NMO is 100 degrees.
NMP = OMP
3x +8 = 4x -6
3x - 4x = -6 -8
-x = -14
x = 14
Now solve any equation
= 3x +8
= 3(14) +8
= 42+8
= 50
Moreover,
NMO is the sum of NMP and OMP
So,
NMO = 50 +50
= 100 degrees.
Therefore we can conclude that The m∠NMO is 100 degrees.
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