Answer:
x = 4 ± [tex]\sqrt{\frac{5}{2} }[/tex]
Step-by-step explanation:
2x^2-16x+27 = 0
<=> 2x^2 - 16 x + 32 -5 = 0
<=> 2(x^2 - 8 x + 16) - 5 = 0
<=> 2 (x^2 - 2. 4. x + 4^2) = 5
<=> 2 (x-4)^2 = 5
<=> (x-4)^2 = 5/2
<=> x-4 = ± [tex]\sqrt{\frac{5}{2} }[/tex]
==> x = 4 ± [tex]\sqrt{\frac{5}{2} }[/tex]
