Question

2x^2-16x+27
complete the square​

Answer 1

(x-4)^2 = 5/2 & x = 2.42, 5.58

Answer 2

Answer:

x = 4 ± $\sqrt{\frac{5}{2} }$

Step-by-step explanation:

2x^2-16x+27 = 0

<=> 2x^2 - 16 x + 32 -5 = 0

<=> 2(x^2 - 8 x + 16) - 5 = 0

<=> 2 (x^2 - 2. 4. x + 4^2) = 5

<=> 2 (x-4)^2 = 5

<=> (x-4)^2 = 5/2

<=> x-4 = ±  $\sqrt{\frac{5}{2} }$

==> x = 4 ±  $\sqrt{\frac{5}{2} }$