Answer:2 ft/s
Explanation:
Given
Length of Pole is 9 ft
Length of Joe is 3 ft
Joe walks away from Pole at the rate 4 ft/s
Let Joe is x m away from Pole so its shadow length is x'
From Similar triangle concept
[tex]\frac{x'}{x+x'}=\frac{3}{9}[/tex]
3x'=x+x'
x=2x'
and it is given [tex]\frac{\mathrm{d} x}{\mathrm{d} t}=4 ft/s[/tex]
Differentiating
[tex]\frac{\mathrm{d} x}{\mathrm{d} t}=2\frac{\mathrm{d} x'}{\mathrm{d} t}[/tex]
[tex]4=2\times \frac{\mathrm{d} x'}{\mathrm{d} t}[/tex]
[tex]\frac{\mathrm{d} x'}{\mathrm{d} t}=2 ft/s[/tex]