Question

URGENT, DUE VERY SOON

A coordinate plane from negative 8 to 8 along the x-axis and from negative 7 to 7 along the y-axis. Which steps should be used to graph the equation y – 4 = y minus 4 equals StartFraction one-third EndFraction left-parenthesis x plus 2 right-parenthesis.(x + 2)? 1. Plot the point (2, 4). 2. From that point, count left 3 units and down 1 unit and plot a second point. 3. Draw a line through the two points. 1. Plot the point (2, 4). 2. From that point, count left 1 unit and down 3 units and plot a second point. 3. Draw a line through the two points. 1. Plot the point (–2,4). 2. From that point, count left 3 units and down 1 unit and plot a second point. 3. Draw a line through the two points. 1. Plot the point (–2,4). 2. From that point, count left 1 unit and down 3 units and plot a second point. 3. Draw a line through the two points.

Answer 1

Answer:

1. Plot the point (–2,4).

2. From that point, count left 3 units and down 1 unit and plot a second point.

3. Draw a line through the two points.

Step-by-step explanation:

Given:

The equation is: $y-4=\frac{1}{3}(x+2)$

Express this in the standard form, $y=mx+b$

Where, $m$ is the slope of the line and $b$ is the y-intercept.

$y-4=\frac{1}{3}((x+2)\\y=\frac{1}{3}((x+2)+4\\y=\frac{1}{3}x+\frac{2}{3}+4\\y=\frac{1}{3}x+\frac{14}{3}$

So, the slope is $\frac{1}{3}$ and y-intercept is $\frac{14}{3}$.

Now, for $x=-2,y=\frac{1}{3}\times -2+\frac{14}{3}=4$

So, first we plot the point $(-2,4)$.

Since, the slope is $\frac{1}{3}$, we have to move 3 units to left and then 1 unit down to plot a second point.

Slope is positive, therefore, we have to move left and then down

Lastly, we have to draw a line passing through these two points to graph the equation $y-4=\frac{1}{3}(x+2)$.