If an athlete expends 2550. kJ/h, how long does she have to play to work off 1.00 lb of body fat? Note that the nutritional calorie (Calorie) is equivalent to 1 kcal, and one pound of body fat is equivalent to about 4.10 × 103 Calories.

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Answer:

[tex]t=6.73h[/tex]

Explanation:

Hello,

In this exercise we first must consider that the energy she has to consume in kJ (taking into account the nutritional calorie) to loss 1.00 lb of body fat is:

[tex]4.10x10^3kcal*\frac{4.1858kJ}{1kcal} =17161.78kJ[/tex]

Now, the spent time to lose that amount of energy (which is reflected in the loss of 1.00 lb), we must apply the formula:

[tex]t=\frac{17161.78kJ}{2550kJ/h}=6.73h[/tex]

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