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A0FE
Displacement (s) of an object equals, velocity (u) times time (t), plus ½ times acceleration (a) times time squared (t2). Use standard gravity, a = 9.80665 m/s2, for equations involving the Earth's gravitational force as the acceleration rate of an object.

Answer:

we can find time using equations of motion

Explanation:

We know that distance traveled by a moving object with given initial velocity, travel time and acceleration is given by the formula  

[tex]\mathrm{s}=\mathrm{u} \mathrm{t}+\frac{1}{2} a t^{2}[/tex]

where u = initial velocity,

a = acceleration due to gravity,  

t = travel time and  

s = distance

Now if the object starts from rest,

we can write initial velocity = 0  

i.e u = 0  

and substitute it in the given formula which makes  

u*t = 0 and gives us

[tex]\mathrm{s}=\frac{1}{2} a t^{2}[/tex]

which can be written in terms of time as [tex]t^{2}=\frac{2 s}{a}[/tex]

or [tex]\mathrm{t}=\sqrt{\frac{2 s}{a}}[/tex]

So, if initial velocity is said to be zero or the object starts from rest point then we can find the time using acceleration and distance/displacement

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