write the point slope form of the line that passes through (5,5) and is parrallel to a line with a slope of 1/4. include all of your work in your final answer. type your answer in the box provided ?

Respuesta :

Answer:

[tex]4y-x = 15[/tex]      

Step-by-step explanation:

We are given the following information in the question:

We have to find the equation of line passing through the point (5,5) anfd parallel to the line with slope [tex]\frac{1}{4}[/tex].

Since the line is parallel, they will have the same slope.

Thus, slope of line = [tex]\displaystyle\frac{1}{4}[/tex]

Point-slope form:

[tex](y-y_1) = m(x-x_1)[/tex],

where m is the slope of line and [tex](x_1,y_1)[/tex] is a point on the line.

Putting all the values, we have the equation of line:

[tex](y-y_1) = m(x-x_1)\\(y-5) = \displaystyle\frac{1}{4}(x -5)\\\\4(y-5) = (x-5)\\4y-20 = x -5\\4y-x = -5+20\\4y-x = 15[/tex]

The above equation is the required equation of the line.

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