Question

A 95 kg fullback is running at 4.0 m/s to the east and is stopped in 0.75 s by a head on tackle by a linebacker heading due west. Calculate the original momentum of the fullback, the impulse exerted on the fullback, the impulse exerted on the linebacker, and the average force exerted on the linebacker

Answer 1

Answer:

Explanation:

Given

mass m=95 kg

velocity v=4 m/s

(a)Momentum of Fullback=P=m v

P=95\times 4=380 kg-m/s

(b)Impulse Exerted =change in momentum

$I=(mv)_{final}-(mv)_{initial}$

I=-380 kg-m/s due to west

(c)Impulse Exerted on line backer=380 kg-m/s due to east

(d)Average Force exerted $=\frac{change\ in\ momentum}{time}$

$F_{avg}=\frac{380}{0.75}=506.66 N$