Question

How fast must a plane fly along the earth's equator so that the sun stands still relative to the passengers? Give your answer in both km/h and mph.The radius of the earth is 6400 km.
part A km/h
part B mph
Part C In which direction must the plane fly, east to west or west to east?
Express your answer using two significant figures.

Answer 1

Answer:

17×10² km/h

10×10² mph

east to west

Explanation:

Circumference of Earth

$2\pi r\\ =2\pi 6400000\\ =12800000\pi\ m=12800\pi km$

Speed = Distance / Time

$Speed=\frac{12800\pi}{24}=1675.51\ km/h$

Converting to mph

$1\ km=\frac{1}{1.60934}\ mi$

$1675.51\ km=1675.51\times \frac{1}{1.60934}\ mi=1041.11\ mi$

The velocity of the plane must be 17×10² km/h or 10×10² mph

The plane must fly east to west