Answer:
Step-by-step explanation:
Given that an advocacy organization surveys 960 canadians and 192 of them reported being born in another country. Similarly, 170 out of 1250 Americans reported being foreign- born
[tex]p_1 = \frac{192}{960} =0.2[/tex]
[tex]p_2 = \frac{170}{1250} =0.136[/tex]
a) the difference in the proportions of foreign born residents from both countries=[tex]|p_1 -p_2|=0.2-0.136\\=0.064[/tex]
b) the pooled proportion of foreign born in both countries combined
=[tex]\frac{192+170}{960+1250} \\=\frac{362}{2210} \\=0.1638[/tex]
c) Std error of difference = 0.01588
d) the value of the z-statistics=4.0296
e) Since p <0.00001, reject that the population difference is 0.There is significant difference