Suppose an advocacy organization surveys 960 canadians and 192 of them reported being born in another country. Similarly, 170 out of 1250 Americans reported being foreign- born find the standard error of the difference in sample proportions.

9. Canada, la fin - The researchers from Exercise 1 want to test if the proportions of foreign bonr are the same in the United States as in Canada.

a) What is the difference in the proportions of foreign born residents from both countries?

b) What is the pooled proportion of foreign born in both countries combined?

c) What is the standard error of the difference in part a?

d) What is the value of the z-statistics?

e) What do you conclude at a = 0.05

Respuesta :

Answer:

Step-by-step explanation:

Given that an advocacy organization surveys 960 canadians and 192 of them reported being born in another country. Similarly, 170 out of 1250 Americans reported being foreign- born

[tex]p_1 = \frac{192}{960} =0.2[/tex]

[tex]p_2 = \frac{170}{1250} =0.136[/tex]

a)   the difference in the proportions of foreign born residents from both countries=[tex]|p_1 -p_2|=0.2-0.136\\=0.064[/tex]

b) the pooled proportion of foreign born in both countries combined

=[tex]\frac{192+170}{960+1250} \\=\frac{362}{2210} \\=0.1638[/tex]

c) Std error of difference = 0.01588

d)  the value of the z-statistics=4.0296

e) Since p <0.00001, reject that the population difference is 0.There is significant difference

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