a coin is taken at random froma purse that contains one penny, 2 nickels, 4 dimes, and 3 quarters. let x be the value of the drawn coin. find the average value of x if we repeat the first draw many times

Respuesta :

Answer:

x = 12.6 pennies

Step-by-step explanation:

total number of coins = 1 + 2+ 4 + 3 = 10 coins

P(penny) =[tex]\dfrac{1}{10}[/tex]

P(nickels) =[tex]\dfrac{2}{10}[/tex]

P(dimes) =[tex]\dfrac{4}{10}[/tex]

P(quarters) =[tex]\dfrac{3}{10}[/tex]

hence average value of the coin

x = Penny x P(Penny) + nickel x P(nickel) + dimes x P(dimes) + quarters x P(quarters)

nickels  = 5 pennies dimes = 10 ; and quarters = 25 pennies

[tex]x = 1 \times \dfrac{1}{10} + 5\times \dfrac{2}{10} +10\times \dfrac{4}{10} +  25\times \dfrac{3}{10}[/tex]

x = 0.1 + 1 + 4 + 7.5

x = 12.6 pennies

hence, the average pennies for the first draw is equal to x = 12.6 pennies

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