Answer:
[tex]\textbf{$a^2 + 4a + 16$}\\[/tex]
Step-by-step explanation:
[tex]\textup{Given:}\\$ \frac{a^3 - 64}{a - 4} $\\\textup{This can be written as:}\\$ (a - 4)(a^2 + 4a + 16) $ \hspace{25mm} $[ (a^3 - b^3) = (a - b)(a^2 + ab + b^2)]$\\[/tex]
[tex]\textup{Here $b = 4$}\\\textup{Now, it can be written as}\\$ \frac{(a - 4)(a^2 + 4a + 16)}{a - 4} $\\\textup{which renders us}\\[/tex]
[tex]$a^2 + 4a + 16$[/tex]
