Answer:
The slope-intercept form of the line whose slope is 5 and that passes through the point (-6,10) is y = 5x + 40
Solution:
We have been asked to find the slope intercept form for the point (-6,10) and slope 5.
The slope intercept form of a line is given in the following way:
y = mx + c --eq1
Where m is the slope of the line and c is the y intercept of the line.
To find c we have to substitute the x and y coordinates in eq1 along with value of the slope ‘m’ of the line.
Now the equation becomes:
[tex]10 = 5 \times -6 + c[/tex]
Now solving for c we get:
10 = -30 + c
c = 40.
So now we to get the slope intercept for we have to substitute the value of m and c in equation 1
This gives us:
y = 5x + 40
Thus the slope intercept form of the line is y = 5x + 40