Answer: B. .131
Step-by-step explanation:
Given : The proportion of college freshmen support increased spending on environmental issues : p= 0.53
Let x be the binomial variable that represents the number of college freshmen support increased spending on environmental issues.
with parameter p = 0.25 n= 6
Using binomial , we have
[tex]P(x)=^nC_xp^x(1-p)^{n-x}[/tex]
Required probability :-
[tex]P(x=3)=^6C_3 (0.25)^3(0.75)^3\\\\=\dfrac{6!}{3!3!}(0.25)^3(0.75)^3\\\\=0.1318359375\approx0.1318[/tex]
Hence, the probability that exactly 3 support increased spending on environmental issues=0.1318
