Answer:
T=655K, W=816kJ/kg
Explanation:
consulting the properties of gases, for Helium we have,
[tex]R=2.0769kJ/kg.K,\\c_p=5.1926kJ/kg.K,\\c_v=3.1156kJ/kg.K,[/tex]
To find the specific volume we use the equation,
[tex]v=\frac{RT}{P}[/tex]
Substituting,
[tex]v=\frac{2.0769*(120+273)}{200*10^3}\\v=4.08m^3/kg[/tex]
Flow work is gived by,
[tex]W_{flow}=Pv\\W_{flow}=200*10^3*4.08=816kJ/kg[/tex]
To find the temperature of the gas in the tank we need
[tex]u_{tank}=h_{line}\\h_{line}=c_pT_{line}\\u_{tank}=c_vT_{tank}[/tex]
So,
[tex]T_{tank}=\frac{c_p T_{line}}{c_v}\\T_{tank}=\frac{5.1926}{3.1156}*343\\T_{tank}=655K[/tex]