Respuesta :

Answer:

on   x= -6

x=-8

this is the answer

The zeros of the function X squared +14 X +48 is -6 and -8

Solution:

Need to find zeros of x squared +14x +48 that means needs to find solution of following quadratic equation

[tex]x^{2}+14 x+48=0[/tex]

On splitting the middle term so that summation of two terms comes 14x and product of two terms be [tex]48x^2[/tex] , we get

[tex]\begin{array}{l}{x^{2}+8 x+6 x+48=0} \\\\ {=>x(x+8)+6(x+8)=0} \\\\ {=>(x+6)(x+8)=0}\end{array}[/tex]

So either x+6 = 0 or x + 8 = 0

when x+6 = 0, x = -6

when x+8 = 0, x = -8

Hence required zeros of [tex]x^2[/tex] + 14x + 48 are -6 and -8.

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