Answer:
Step-by-step explanation:
No of trials = 290
no of heads =160
Sample proportion p = [tex]\frac{160}{290} =0.552[/tex]
[tex]H_0: p=0.5\\H_a: p \neq 0.5[/tex]
(Two tailed test)
p difference = [tex]0.552-0.5=0.052[/tex]
Std error = [tex]\sqrt{\frac{0.5(0.5)}{290} } \\=0.02936[/tex]
Z statistic = 1.77
p value = 0.076
p value >0.05 hence accept that prob for heads is 0.5
If it is 1%p>0.01 hence accept null hypothesis again