Question

You are trying to find out how high you have to pitch a water balloon in order for it to burst when it hits the ground. You discover that the balloon bursts when you have pitched it to a height of 12 m. With what velocity did the balloon hit the ground? The acceleration of gravity is 9.8 m/s

Answer 1

Answer:

15.33623 m/s

Explanation:

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -9.8\times 12}\\\Rightarrow u=15.33623\ m/s$

The initial velocity by which the balloon should be thrown up is 15.33623 m/s

At the maximum height the initial velocity becomes 0

$v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 9.8\times 12+0^2}\\\Rightarrow v=15.33623\ m/s$

Hence, the balloon will hit the ground at 15.33623 m/s