Answer:
2
Explanation:
So for solving this problem we need the local heat transfer coefficient at distance x,
[tex]h_x=cx^{-1/2}[/tex]
We integrate between 0 to x for obtain the value of the coefficient, so[tex]\bar{h}_x =\frac{1}{x} \int\limit^x_0 h_x dx\\\bar{h}_x = \frac{c}{x} \int\limit^x_0 \frac{1}{\sqrt{x}}dx\\\bar{h}_x = \frac{c}{c} (2x^{1/2})\\\bar{h}_x = 2cx^{-1/2}[/tex]
Substituing
[tex]\bar{h}_x=2h_x\\\frac{\bar{h}_x}{h_X}=2[/tex]
The ratio of the average convection heat transfer coefficient over the entire length is 2