Answer:
4032 different tickets are possible.
Step-by-step explanation:
Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.
To find : How many different tickets are possible ?
Solution :
In the first race there are 9 ways to pick the winner for first and second place.
Number of ways for first place - [tex]^9C_1=9[/tex]
Number of ways for second place - [tex]^8C_1=8[/tex]
In the second race there are 8 ways to pick the winner for first and second place.
Number of ways for first place - [tex]^8C_1=8[/tex]
Number of ways for second place - [tex]^7C_1=7[/tex]
Total number of different tickets are possible is
[tex]n=9\times 8\times 8\times 7[/tex]
[tex]n=4032[/tex]
Therefore, 4032 different tickets are possible.
