Question

In a group assignment, students are required to fill 10 beakers with 0.720 M CaCl2. If the molar mass of CaCl2 is 110.98 g/mol and each beaker must have 250. mL of solution, what mass of CaCl2 would be used?
1)3.13 g
2)38.5 g
3)200 g
4)617 g

Answer 1

Total volume = 10*0.250 liters = 2.5 liters
M = n / V (liters)
Total moles: n = M*V = 0.720mol/liter *2.5 liter =1.8 mol

MM = grams / n --> grams = n*MM = 1.8 mol * 110.98 g/mol = 199.8 grams

Answer: option 3) 200 g.

Answer 2

200 g is the mass of $CaCl_2$ would be used. Hence, option C is correct.

Define the molarity of a solution.

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per litres of a solution. Molarity is also known as the molar concentration of a solution.

Total volume = 10 x 0.250 liters = 2.5 liters

M = n ÷ V

Total moles: n = M x V

= 0.720mol/liter  x 2.5 liter

=1.8 mol

Molar mass = grams / n

1.8 mol x 110.98 g/mol

= 199.8 grams

Hence, option C is correct.

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